16x^2+72x-144=0

Solution for 16x^2+72x-144=0 equation:

16x^2+72x-144=0

a = 16; b = 72; c = -144;
Δ = b2-4ac
Δ = 722-4·16·(-144)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-120}{2*16}=\frac{-192}{32}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+120}{2*16}=\frac{48}{32}
=1+1/2
$